Question 214817
For the Mr. Arlington contest, there were 206 more tickets sold at the door than were sold in advance. The tickets sold at the door cost $10 and the tickets sold in advance cost $6. The total  amount of sales for both types of tickets was $6828. How many of each type of ticket was sold?


Step 1.  Let x be the number of tickets sold in advance.


Step 2.  Let x+206 be the number of tickets sold at the door.


Step 3.  Let 6x be the cost of the tickets sold in advance.


Step 4.  Let 10(x+206) be the cost of the tickets sold at the door.


Step 5.  Then 6x+10(x+206)=6828 be the cost of the total tickets sold.


Step 6.  The following steps will solve the equation in Step 5.


*[invoke explain_simplification "6x+10(x+206)=6828" ]


With x=298  , then x+206=298+206=504


Step 7.  The number of tickets sold in advance is 298 and the number of tickets sold at the door is 504.


I hope the above steps were helpful.


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Good luck in your studies!


Respectfully,
Dr J