Question 214792
Phillip has 10 coins in his pocket.
 Phillip has the same number of pennies as quarters and the same number of dimes as nickels. 
He also has one more nickel than he does pennies.
 If he has 97 cent how many coins of each type does he have?
:
Let x = no. of pennies & quarters
Let y = no. of dimes & nickels
:
"He has one more nickel than pennies
y = x + 1
:
Total no. of coins
2x + 2y = 10
simplify, divide by 2
x + y = 5
:
we know: y = x+1
therefore
x = 2 ea pennies & quarters
y = 3 ea nickels & dimes
:
Check using $amt
.01(2) + .25(2) + .05(3) + .10(3) =
.02 + .50 + .15 + .30 = .97