Question 29427
log( base 2) x + log (base 4) x = 3
log(base 2)x = 3 - log(base 4)x
4^(log(base 2)x = 4^(3 - log(base 4)x)
2^(log(base 2)x * 2^(log(base 2)x = 4^3 / 4^log(base 4)x
x^2 = 4^3 / x
{{{x^3 = 4^3}}}
{{{x = 4}}}
check
log(base 2)4 + log(base 4)4 = 3
{{{2 + 1 = 3}}}