Question 214721
{{{AreaOfrectangle = Length * Width}}}

Given dimensions are {{{x + 10}}} feet and {{{x - 11}}} feet and area = 490 square feet

{{{(x+10)*(x-11) = 490}}}
{{{x^2 - 11x + 10x - 110 = 490}}}
{{{x^2 -x -110 = 490}}}
{{{x^2 -x - 600 = 0}}}
{{{(x-25)(x+24) = 0}}}
x = 25
If x - 25, then x+10 = 35 and x-11 = 14