Question 214739
{{{6x+2y=8}}}  Equation A
{{{-3x+y=20}}}  Equation B


Step 1.  Multiply Equation B by 2 and Add the two equations.


{{{-3x+y=20}}}

{{{-6x+2y=40}}}
{{{6x+2y=8}}}

Step 2.  This yields


{{{4y=48}}} or {{{y=12}}}


Step 3.  Substitue y=12 into equation A or B.  Here's for Equation A


{{{6x+2*12=8}}}


{{{6x=-16}}}


{{{x=-16/6=-8/3}}}


Step 4.  ANSWER:  The solution is x=-8/3 and  y=12.


As a check here's the solution using SUBSTITUTION:


*[invoke linear_substitution "x", "y", 6, 2, 8, -3, 1, 20]


The results are the same as before.


I hope the above steps were helpful. 


For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.


And good luck in your studies!


Respectfully,
Dr J