Question 214712
<h4>x-intercept</h4>

To find the x-intercept, plug in {{{y=0}}} and solve for x



{{{4x-2y=8}}} Start with the given equation.



{{{4x-2(0)=8}}} Plug in {{{y=0}}}.



{{{4x-0=8}}} Multiply {{{-2}}} and 0 to get 0.



{{{4x=8}}} Simplify.



{{{x=(8)/(4)}}} Divide both sides by {{{4}}} to isolate {{{x}}}.



{{{x=2}}} Reduce.



So the x-intercept is *[Tex \LARGE \left(2,0\right)].



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<h4>y-intercept</h4>

To find the y-intercept, plug in {{{x=0}}} and solve for y



{{{4x-2y=8}}} Start with the given equation.



{{{4(0)-2y=8}}} Plug in {{{x=0}}}.



{{{0-2y=8}}} Multiply {{{4}}} and 0 to get 0.



{{{-2y=8}}} Simplify.



{{{y=(8)/(-2)}}} Divide both sides by {{{-2}}} to isolate {{{y}}}.



{{{y=-4}}} Reduce.



So the y-intercept is *[Tex \LARGE \left(0,-4\right)].


Now plot the points


{{{ drawing(500, 500, -10, 10, -10, 10,
grid(0),
graph(500, 500, -10, 10, -10, 10,0)
circle(2,0,0.05),circle(2,0,0.08),circle(2,0,0.10),circle(2,0,0.12),circle(2,0,0.15),
circle(0,-4,0.05),circle(0,-4,0.08),circle(0,-4,0.10),circle(0,-4,0.12),circle(0,-4,0.15)
)}}} 



and draw a straight line through them to graph the equation {{{4x-2y=8}}}



{{{ drawing(500, 500, -10, 10, -10, 10,
grid(0),
graph(500, 500, -10, 10, -10, 10,(8-4x)/(-2))
circle(2,0,0.05),circle(2,0,0.08),circle(2,0,0.10),circle(2,0,0.12),circle(2,0,0.15),
circle(0,-4,0.05),circle(0,-4,0.08),circle(0,-4,0.10),circle(0,-4,0.12),circle(0,-4,0.15)
)}}} Graph of {{{4x-2y=8}}}