Question 214660
{{{2/x-4/(x+1)=3}}}


Step 1.  Multiply by x(x+1) to both sides to get rid of denominators.


{{{x(x+1)*(2/x-4/(x+1))=x(x+1)3}}}


Step 2.  Simplify above equation


{{{2(x+1)-4x=3x^2+3x}}}


{{{3x^2+3x=2x+2-4x=-2x+2}}}


{{{3x^2+3x+2x-2=-2x+2+2x-2=0}}}


{{{3x^2+5x-2=0}}}


Step 3.  We can then use the quadratic formula to solve the above equation given as {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}


where a=3, b=5, and c=-2


*[invoke quadratic "x", 3, 5, -2 ]


Step 4. ANSWER:  The solutions are {{{1/3}}} and {{{-2}}}


I hope the above steps were helpful. 


For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.


And good luck in your studies!


Respectfully,
Dr J