Question 214669
First, find the volume of the cylindrical tank:
{{{V = (pi)r^2h}}} where r = the radius of the circular cross-section and h = the height (or depth) of the tank.
The cylinder cross-section has a diameter of 54" so its radius is {{{54/2 = 27}}}inches. The height (depth) is 27".
{{{V = (pi)*(27)^2*27}}}
{{{V = (pi)*19683}}}
{{{V = 61835.97}}}cubic inches.
Since you didn't say what liquid is in the tank, I'll assume that it's water and, for water, 1 gallon = 231 cubic inches.
So you need to know how many times will 231 cubic inches go into 61835.97 cubic inches, so you have to divide:
{{{G = 61835.97/231}}}
{{{G = 267.7}}} gallons.