Question 214343
a) Find the area of the region bounded by the parabola:
f(x) 2x^2, g(x) = 3x^2 + 5 and the line y = 8.
I think you have not typed the problem correctly. As stated, you have two parabolas and they do not intersect each other. So it not clear what the region is. See the graph below which include all three functions:
{{{graph(400, 400, -5, 5, -1, 11, 2x^2, 3x^2 + 5, 8)}}}<br>
b) Find dy/dx given that y = l+x(^2)e^(y)
If we call {{{u = 1}}}, {{{v =  x^2}}} and {{{w = e^y}}}, then u' = 0, v' = 2x and, using the chain rule, w' = y'*{{{e^y}}}. Substituting u, v and w into the original equation we get:
y = u + v*w
Using basic rules of differentiation, we get:
y' = u' + v*w' + w*v'
Replacing u', v, v', w and w' (from above) we get:
y' = 0 + {{{x^2}}}*(y'*{{{e^y)}}} + {{{e^y*(2x)}}}
Now we use Algebra to simplify and solve for y':
y' = {{{x^2*e^y}}}*y' + {{{2x*e^y}}}
Subtract {{{x^2*e^y}}}*y' from each side:
y' - {{{x^2*e^y}}}*y' = {{{2x*e^y}}}
Factoring out y' on the left:
y'*{{{(1 -x^2*e^y) = 2x*e^y}}}
Dividing both sides by {{{(1 -x^2*e^y)}}}:
y' = {{{(2x*e^y)/(1 -x^2*e^y)}}}