Question 214435
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Let *[tex \Large w] represent the width.  Then *[tex \Large w + 7] must represent the length.  The area is the product of the length times the width, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ w^2 + 7w = 228]


Put it in standard form and then solve the quadratic for *[tex \Large w].  Exclude the extraneous negative root.  The positive root will be the width.  Add 7 to get the length.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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