Question 214462
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If the weight of the final exam is 45%, then the weight of all the other exams must be 55%.  Since there are 5 other exams, each of them is worth 55 divided by 5 equals 11%.


So you can write the following equation:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ .11(80+84+71+65+90) + .45x = 87]


Solve for *[tex \Large x] and you have your answer.  She is going to have to do a LOT better than what she averaged on the first 5 exams.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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