Question 214455
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If both *[tex \Large \angle 1] and *[tex \Large \angle 2] are complementary to *[tex \Large \angle 3], then *[tex \Large \angle 1 = \angle 2].


Since *[tex \Large \angle 2 = 2x + 24] and *[tex \Large \angle 3 = 8x - 6], and they are complementary we can say:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x + 24 + 8x - 6 = 90]


Which is to say:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 10x = 72]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x = 7.2]


Hence


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \angle 2 = 2(7.2) + 24 = 38.4]


and therefore


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \angle 1 = \angle 2 = 38.4]


As for your second question, I think you meant which one <b><i>is</i></b> true because three of the given statements are false (A, B, and D) and only one is true (C).


A: If *[tex \Large x = 4], then *[tex \Large x^2 = 16 \neq 6]


B: If *[tex \Large x^3 = -27], then *[tex \Large x = -3 \neq 3]


C: If *[tex \Large x = 2], then *[tex \Large x^2 = 4 = 4] True


D: If *[tex \Large x^2 = 49], then *[tex \Large x = \pm 7] Half right, therefore half wrong, therefore False


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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