Question 214363
x = 10's digit
y = units
;
Let number be: 10x + y
:
the ones digit of a two-digit number is twice the tens digit.
y = 2x
:
 If the number exceeds the sum of its digits by 36,
10x + y = (x + y) + 36
10x - x + y - y = 36
9x = 36
x = {{{36/9}}}
x = 4
:
y = 2(4)
y = 8
:
48 is the number
;
;
Check solution in the statement:
the number exceeds the sum of its digits by 36,
48 = 4 + 8 + 36