Question 214397
Is (5,0) a solution of the system 
x-4y=5 
2x-3y=10
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Multiply thru the 1st equation by 2 to get:
2x-8y = 10
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Subtract that equation from the 2nd equation to get:
5y = 0
y = 0
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Substitute that into x -4y = 5
x -4*0 = 5
x = 5
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So you are correct; (5,0) is the solution.
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Cheers,
Stan H.