Question 214272
Write an equation in slope-intercept form of a line satisfying the following conditions:  passing through (5,6) and perpendicular to x=7


Step 1. The slope-intercept form is given as y=mx+b where m is the slope and b is the y-intercept.  The y-intercept occurs at x=0 or point (0,b).


Step 2.  x=7 is a vertical line or parallel to the y-axis.  So a line perpendicular to x=7 is a horizontal line parallel to the x-axis. 


Step 3.  Therefore y=b is a horizontal line parallel to the x-axis.  Now, the line needs to pass through point (5,6) or x=5 and y=6. Then,  y=b=6 or y=6 is the equation of the line.


Step 4.  ANSWER:  The equation is y=6  where slope m=0 and y-intercept b=6.


I hope the above steps were helpful. 


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And good luck in your studies!


Respectfully,
Dr J