Question 214228
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Let *[tex \Large w] represent the width of the rectangle.  Then the length of the rectangle must be *[tex \Large w + 12], and the perimeter must be *[tex \Large 16w].


The perimeter of a rectangle is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P = 2l + 2w]


Substitute:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 16w = 2(w + 12) + 2w]


Solve for *[tex \Large w] to get the width.  Add 12 to get the length.




John
*[tex \LARGE e^{i\pi} + 1 = 0]
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