Question 214176
Find two consecutive odd integers such that their product is 15 more than 3 times their sum.


Step 1.  Let n be an odd integer then n+2 be the next odd consecutive integer


Step 2.  n(n+2) is the product of the two odd integers.


Step 3.  n+n+2 is the sum of the two odd integers.


Step 4.  n(n+2)=15+3(n+n+2)  product is 15 more than sum.


Step 5.  Solve the equation in Step 4 using the following steps.


*[invoke explain_simplification "n*(n+2)=15+3*(n+n+2)" ]


Step 6. There are two solutions 7 and 9 is one solution set and the other -3 and -1 is another solution set.


I hope the above steps were helpful. 


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And good luck in your studies!


Respectfully,
Dr J