Question 214191
A particle starts from the origin at t = 0 with
an initial velocity having an x component of
17.7 m/s and a y component of −10.8 m/s.
The particle moves in the xy plane with an
x component of acceleration only, given by
4.51 m/s2. 
a. Determine the x component of velocity af-
ter 7.16 s. Answer in units of m/s. 49.9916 m/s
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b. Find the speed of the particle after 7.16 s.
Answer in units of m/s.
{{{v = sqrt(x^2 + y^2)}}} x & y are respective speeds
{{{v = sqrt(49.9916^2 + 10.8^2)}}}
{{{v = sqrt(2615.8)}}}
v =~ 51.145 m/sec
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c. Find the magnitude of the displacement vec-
tor of the particle after t = 7.16 s. Answer in
units of m.
x = 7.16*(17.7 + 49.9916)/2
x = 242.34 meters
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y = - 7.16*10.8
y = 77.328 meters
{{{s = sqrt(x^2 + y^2)}}}
{{{s = sqrt(64707)}}}
s = 254.375 meters