<PRE><B>Question 214173</B>
Joshua had 142 coins, all nickels and quarters. The total amount was $15.30. HOw many coins of each type did he have? 
-----------------
n + q = 142 (# of coins)
5n + 25q = 1530 (value of coins)
q = 142-n (from eqn 1)
Sub for q into eqn 2
5n + 25q = 1530
5n + 25(142-n) = 1530
5n + 3550 - 25n = 1530
-20n = -2020
n = 101 nickels
q = 41 quarters
--------------
101*5 + 41*25 = 505 + 1025
= 1530

</PRE>