Question 214097
Find two consecutive even integers such that three times the lesser integer, added to the larger integer, is 58.


Step 1.  Let n be an even integer and n+2 be the next consecutive even integer


Step 2.  3n  be three times the lesser integer


Step 3.  3n+n+2  be three times the lesser integer added to the larger integer n+2


Step 4.  3n+n+2=58  be three times the less integer added to the larger integer n+2 is 58.


Step 5.  The following steps will solve the equation 3n+n+2=58.


*[invoke explain_simplification "3n+n+2=58" ] 


Then n+2=16 when n=14


Check 3*14+16=58. So it works!!


Step 6. ANSWER:  The integers are 14 and 16.  


I hope the above steps were helpful. 


For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.


And good luck in your studies!


Respectfully,
Dr J