Question 214092
Set one leg to x and the hypoteneuse to x+3. Then use the Pythagorean theorem:
{{{x^2+9^2=(x+3)^2}}}
{{{x^2+81=x^2+6x+9}}}
{{{6x+9=81}}}
{{{6x=72}}}
{{{x=12}}}
So the leg is 12, and the hyp. is 12+3=15
===============
Good Luck,
tutor_paul@yahoo.com