Question 214085
Some 5% alcohol Solution is mixed with another 20% alcohol solution to get a mixture of 25 liters of 14% solution. Find the amount of each alcohol solution before mixing.
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Let x = amount of 5% solution
then because the total mixture is 25 liters we have
25-x = amount of 20% solution
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Our equation:
.05x + .20(25-x) = .14(25)
.05x + 5 - .20x = 3.5
5 - .15x = 3.5
-.15x = -1.5
x = 10 liters (5% alcohol solution)
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20% alcohol solution:
25-x = 25-10 = 15 liters