Question 214010
How do you solve this problem using the midpoint formula? R(2,6) M(-1,1)


I assume R is one endpoint and the M is the midpoint


Let (x,y) be the other endpoint.  Then for this example the midpoint is calculated by averaging the x and y coordinates of the endpoints.  That is,


{{{-1=(x+2)/2}}} and  {{{1=(y+6)/2}}}


{{{-2=x+2}}} and {{{2=y+6}}}


{{{x=-4}}} and {{{y=-4}}}


So the other endpoint is (-4,-4)


As a check between the two endpoints (-4,-4) and (2,6), let's calculate the midpoint.


{{{(-4+2)/2=-1}}} is the x-coordinate for the midpoint.


{{{(-4+6)/2=1}}} is the y-coordinate for the midpoint.


So the midpoint is (-1,1) which is same as before.


I hope the above steps were helpful.


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Good luck in your studies!


Respectfully,
Dr J