Question 213912
Find the three consecutive odd integers such that the sum of the first two odd integers exceeds the third by 9.


Step 1.  Let n be an odd integer, n+2 and n+4 be the next two consecutive odd integers.


Step 2.  Let n+n+2  is the sum of the first two integers


Step 3.  Then, n+n+2=n+4+9 Since the sum of n+n+2 is 9 more than the third integer given as n+4


Step 4.  Solve the above equation using the following steps.


*[invoke explain_simplification "n+n+2=n+4+9" ]


Step 5. ANSWER:  So the integers are 11, 13 and 15.


Check 11+13=24 which is 9 more than 15.  So it checks!


I hope the above steps were helpful. 


For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.


And good luck in your studies!


Respectfully,
Dr J