Question 29355
{{{8/16}}} can be thought of as {{{(8*1)/(8*2)}}}. we can then cancel the 8's leaving {{{(1*1)/(1*2)}}} --> 1/2.


This is the "full" method. In reality, all you need to do is look at the 2 numbers and see what goes into both and divide by that number.


As for {{{(2xy)/x}}}. Again, what is common to both the numerator and denominator? Answer is x, so we can cancel them, leaving us with just 2y.


jon.