Question 213614
The distance between two numbers is 18. Twice the smaller plus three times the larger is 74. What are the numbers? 
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Let the larger be "x":
Let the smaller be "y":
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Equations:
x-y = 18
2y+3x = 74
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Rearrange the 1st equation:
x = y+18
Substitute into the 2nd equation to solve for "y";
2y + 3(y+18) = 74
2y + 3y + 54 = 74
5y = 20
y = 4 (the smaller number)
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Since x = y+18, x = 4+18 = 22 (the larger number)
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Cheers,
Stan H.