Question 213480
Suppose that the length of a certain rectangle is 9 meters less than two times its width. The perimeter of the rectangle is 42 meters. Find the length and width of the rectangle.


Step 1.  Let l = 2w-9 be the length of rectangle and let w be the width


Step 2.  Let P = 42 meters be the perimeter.  Perimeter means adding the 4 sides of a rectangle.  So,


{{{P=2w-9+2w-9+w+w}}}


{{{P=6w-18}}}


{{{P=6w-18=42}}}


Step 3.  Add 18 to both sides of equation to get 4w by itself



{{{P=6w+18-18=42+18}}}


{{{6w=60}}}


Step 4.  Divide 6 to both sides of equation


{{{6w/6=60/6}}}


{{{w= 10 }}}


Step 5.  w = 10 meters is the width of the rectangle and length is 11 m since


l=2w-9=11


Check P=2w+2l=2(10)+2(11)=20+22=42 So w = 10 meters and l = 11 meters is the solution.


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And GOOD LUCK in your studies!


Respectfully
Dr J