Question 213467
{{{d = r*t}}}
I think (1 mi = 5280 ft)
(95 mi/hr)(5280 ft/ 1 mi) = 501600 ft/hr 
{{{56 = 95*5280*t}}} ft
{{{t = .000111643}}} hr
(.000111643 hr)*(3600 sec/hr) = t in sec
{{{t = .000111643*3600}}} sec
{{{t = .402}}} sec