Question 29337
(4-i)^2+2(3-2i)-4

1st solve (4-i)^2 with the identity (a-b)^2= a^2 + b^2 - 2ab...and we get 

 [(4)^2 + (i)^2 - 2(4)(i)] + 2(3-2i)-4 

[16 + i^2 - 8i ] + 2(3-2i)-4

Now,lets solve the other part i.e..2(3-2i)-4....here is the simple multipication requried...


[16 + i^2 - 8i ] + 6 - 4i -4

or, 16 + i^2 - 8i  + 6 - 4i -4

Now, put together the like variables ....we get..

i^2 - 8i-4i +16+6-4

i^2 -12i +22-4

i^2 -12i +18.......ANSWER

if further factorization is requried,,,,I suggest that you must 1st check the equation and then let me know...