Question 213411
FIND THREE CONSECUTIVE ODD INTEGERS SUCH THAT FOUR TIMES THE MIDDLE INTEGER IS TWICE THE SUM OF THE OTHER TWO INTEGERS


Step 1.  Let n be an odd integer, n+2 be the next consecutive odd or middle integer, and n+4 be the second consecutive odd integer


Step 2.  4(n+2)=2(n+n+4)  since middle integer is twice the sum of n+n+4


{{{4(n+2)=2(2n+4)}}}


{{{4n+8=4n+8}}}


{{{0=0}}}


Step 3.  The above result means any 3 consecutive odd integers will satisfy the above equation or problem statement.  For example,


1, 3, 5 implies 4(3)=2(1+5) or 12=12


3, 5, 7 implies 4(5)=2(3+7) or 20=20


5, 7, 9 implies 4(7)=2(5+9) or 28=28



I hope the above steps were helpful.


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Good luck in your studies!


Respectfully,
Dr J