Question 213431
Find the ratio, reduced to lowest terms, of the volume of a sphere with a radius of 3 inches to the volume of a sphere with a radius of 6 inches


Step 1.  Let  {{{V1=4pi*r1^3/3}}} and {{{V2=4pi*r2^3/3}}}  where V1 volume of Sphere 1 with radius r1=3 and V2 volume of Sphere 2 with radius r2=6.  And {{{pi=3.14159}}}


Step 2.  Now find V1/V2


{{{V1/V2=(4pi(r1)^3/3)/(4pi(r2)^3/3)}}}


{{{V1/V2=r1^3/r2^3=(r1/r2)^3}}}


{{{V1/V2=(3/6)^3=(1/2)^3}}}


{{{V1/V2=1/8}}}



I hope the above steps were helpful.


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Respectfully,
Dr J