Question 213442
Let x = age of son now
y= age of father now


x-2= age of son 2 years ago
y-2 = age of father 2 years ago


x+3 = age of father 3 years from now
y+3= age of father 3 years from now


y-2=4(x-2)
y+3=3(x+3)


y-2=4x-8,  so y = 4x-6
y+3=3x+9, so y=3x+6


Now, since 
y=4x-6 and y=3x+6,
 4x-6=3x+6
x=12  Age of son now
y=3x+6
y=3(12)+6
y=36+6=42 Age of father now


Check:  

2 years ago, son was 10 and father was 40--(four times as old!)
3 years from now, the son will be 15 and father will be 45--(three times as old!!)


I would love to recommend my website to you on this, but I just don't have anything like this on it!!!  


R^2


Dr. Robert J. Rapalje, Retired
Seminole Community College
Altamonte Springs Campus
Florida