Question 213416
The number of households that bought rice cookers was
{{{.15*400 = 60}}}
Each household bought 1 rice cooker
Let {{{a}}} = the number sold by salesman A
Let {{{b}}} = the number sold by salesman B
Let {{{c}}} = the number sold the salesman C
(1) {{{a + b + c = 60}}}
(2) {{{a/b = 3/4}}}
(3) {{{b/c = 4/5}}}
This is 3 equations with 3 unknowns, so it should be solvable
From (2)
{{{a = (3/4)*b}}}
From (3)
{{{c = (5/4)*b}}}
Now rewrite (1)
{{{(3/4)*b + b + (5/4)*b = 60}}}
Multiply both sides by {{{4}}}
{{{3b + 4b + 5b = 240}}}
{{{12b = 240}}}
{{{b = 20}}}
and
{{{a = (3/4)*b}}}
{{{a = (3/4)*20}}}
{{{a = 15}}}
and
{{{c = (5/4)*b}}}
{{{c = (5/4)*20}}}
{{{c = 25}}}
The 3 salesmen charged $60 for each rice cooker
A's $ sales = {{{15*60 = 900}}}
B's $ sales = {{{20*60 = 1200}}}
C's $ sales = {{{25*60 = 1500}}}
A's commision = {{{.04*900 = 36}}}
B's commision = {{{.04*1200 = 48}}}
C's commision = {{{.04*1500 = 60}}}
Hope I didn't misread the problem!