Question 213355
Can you please help me with this equation?
2m^(2/3)+3m^(1/3)-2=0, please show me the steps and get back asap (tonight if possible)
Thanks so much


{{{2m^(2/3) + 3m^(1/3) - 2 = 0}}}


{{{(2m^(1/3) - 1)(m^(1/3) + 2) = 0}}} ------- Factor just like any ordinary trinomial

{{{2m^(1/3) - 1 = 0}}}, or, {{{m^(1/3) + 2 = 0}}}


{{{2m^(1/3) = 1}}}, or, {{{m^(1/3) = - 2}}}


{{{m^(1/3) = 1/2}}}, or, {{{m^(1/3) = - 2}}}

{{{m^(1/3)^3 = (1/2)^3}}}, or, {{{m^(1/3)^3 = (-2)^3}}} ----- Cubing both sides of the 2 equations


{{{highlight_green(m = 1/8)}}}, or {{{highlight_green(m = -8)}}}