Question 213374
Suppose {{{h(t)=t^2+11t+7}}}. Find the instantaneous rate of change of h(t)
with respect to t at t=2. 


This is a calculus problem involving derivatives. 


Step 1.  So the first derivative of h(t) or h'(t) is the rate of change of h(t) with respect to t.


First derivative of h(t) = h'(t) = {{{2t+11}}}


Step 2.  At t=2,  then h'(t)=2*2+11 = 15.


Step 3.  The instantaneous rate of change of h(t) = h'(t) = 15.


I hope the above steps were helpful.


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Good luck in your studies!


Respectfully,
Dr J