Question 213324
 4x(to the fourth power)y(to the fourth power) + 2x(squared)y(squared) + .75= 0
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{{{4x^4y^4 + 2x^2y^2 + 0.75 = 0}}}
Sub x for x^2y^2 to use the onsite solver
*[invoke solve_quadratic_equation 4,2,.75]
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{{{x^2y^2 = (-1+i*sqrt(2))/4}}}
{{{x^2 = (-1+i*sqrt(2))/4y^2}}}
{{{x = +sqrt((-1+sqrt(2)))/2y}}}
{{{x = -sqrt((-1+sqrt(2)))/2y}}}
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{{{x^2y^2 = -(-1+i*sqrt(2))/4}}}
{{{x^2 = -(-1+i*sqrt(2))/4y^2}}}
{{{x = +i*sqrt(-1+sqrt(2))/2y}}}
{{{x = -i*sqrt(-1+sqrt(2))/2y}}}