Question 213319
Find All values of (y) such that the distance between (4,y) and (-3,9) is 21.
---
21^2 = (4--3)^2 + (y-9)^2
441 = 49 + y^2 -18y + 81
y^2 - 18y -311 = 0
Solve using the quadratic formula.
Cheers,
Stan H.