Question 213198
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{{{sqrt(3/4) + sqrt(12)}}}

Write the first term as the quotient of two square roots

{{{sqrt(3)/sqrt(4) + sqrt(12)}}}

Replace {{{sqrt(4)}}} by {{{2}}}

{{{sqrt(3)/2 + sqrt(12)}}}

Now break {{{12}}} into {{{4*3}}}

{{{sqrt(3)/2 + sqrt(4*3)}}}

Write the second term as the product of two square roots

{{{sqrt(3)/2 + sqrt(4)sqrt(3)}}}

Replace {{{sqrt(4)}}} by {{{2}}}

{{{sqrt(3)/2 + 2sqrt(3)}}}

Put {{{1}}} under the second term:

{{{sqrt(3)/2 + (2*sqrt(3))/1}}}

Get LCD of 2 and multiply top and bottom by {{{2}}}:

{{{sqrt(3)/2 + (2*sqrt(3)*2)/(1*2)}}}

{{{sqrt(3)/2 + (4*sqrt(3))/2}}} 

Write as one fraction:

{{{(sqrt(3) +4*sqrt(3))/2}}}

Put {{{1*""}}} in front of the first term:

{{{(1*sqrt(3) +4*sqrt(3))/2}}}

Combine like terms

{{{(5sqrt(3))/2}}}

Edwin</pre>