Question 213062
Let h = Henry's present age
Let c = Cheryl's present age
;
Write an equation for each statement:
:
Henry is ten more than two times as old as Cheryl.
h = 2c + 10
:
 In 20 years the sum of their ages will be 92.

(h+20) + (c+20) = 92
h + c + 40 = 92
h + c = 92 - 40
h + c = 52
:
 How old is Cheryl now?
:
Replace h with (2c+10)
2c + 10 + c = 52
2c + c = 52 - 10
3c = 42
c = {{{42/3}}}
c = 14 yrs is Cheryl's present age
;
:
Check solution:
Find h: h + 14 = 52; h = 38
Check solution in the statement:
"In 20 years the sum of their ages will be 92."
38 + 20 + 14 + 20 = 92