<PRE><B>Question 213061</B>
The width of a rectangle is 9 less than twice its length. If the area of the rectangle is 100 centimeters squared, what is the length of the diagonal?
So far i have this: 
width = W= 2L-9
length = L 
L(2L-9)=100
2L^2-9L-100=0 
L = [9 +- sqrt(81 - 4*2*-100)]/4
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L = [9 +- sqrt(881)]/4
Positive solution:
L = [9 + 29.68]/4
Length = 9.67 cm
Width = 2(9.67)-9 = 10.34
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Cheers,
Stan H.
</PRE>