Question 213021

Let the amount invested at 9% be N
Then the amount invested at 12% is 5,000 - N


Now, the interest earned at 9%, less $198 equals the einterest earned at 12%


Therefore, we'll have: .09N - 198 = .12(5,000 - N)


.09N - 198 = 600 - .12N


.09N + .12N = 600 + 198


.21N  =  798


{{{N = 798/.21}}} = $3,800


We can conclude that N, or the amount invested at 9% is: ${{{highlight_green(3800)}}} 

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Check
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Amount invested at 9% = $3,800, and interest earned at 9% = (.09 * 3,800) = $342


Amount invested at 12% = $1,200 (5,000 - 3,800), and interest earned at 12% = (.12 * 1,200) = $144


Difference: $198 ($342 - $144), with 9% interest earned ($342) being $198 more than 12% interest earned ($144).