Question 212928
(2,-1) and (-1,-4)


We 1st determine the slope, using the slope formula, m = {{{(y[2]-y[1])/(x[2]-x[1])}}} -----> {{{(-4--1)/(-1-2)}}} = {{{(-3)/-3}}} = 1


Using the slope, or m = 1, we then plug the information into the point-slope formula to determine our equation


Point-slope formula: {{{y - y[1] = m(x - x[1])}}} ----> y - -1 = 1(x - 2) ----> y + 1 = x - 2 ------> y = x - 3. 


Therefore,the equation of the line which passes through the points (2,-1) and (-1,-4) is: {{{highlight_green(y = x - 3)}}}