Question 212968
Let h be the length of the hypotenuse. Then one side is h/2 and the third side is h-4.
Since it is a right triangle, you know that
{{{h^2 = (h/2)^2 + (h-4)^2}}}
{{{h^2 = h^2/4 + h^2 -8h + 16}}}
{{{0 = h^2/4 - 8h + 16}}}
{{{0 = h^2 - 32h + 64}}}
Use the quadratic equation to solve
*[invoke quadratic "x", 1, -32, 64]

Since one of the answer is too short to make that number -4 positive, the hypotenuse is ~29.85