<PRE><B>Question 29268</B>
Your directions of the original data are not given.


[v1] = 160cos(65)i + 160sin(65)j
[v2] = 152cos(58)i + 152sin(58)j
[vT] = [v1] + [v2]


[vT] = 149.17i +273.91j


||V|| = {{{sqrt((149.17)^2+273.91)^2)}}}
||V|| = {{{sqrt(97278.37)}}}
||V|| = 311.89


Use sine law to find the direction: (note: your units are not given, like north, west, east, south)


From sine law: sinT/160 = sin58/311.89
sinT=(160sin(58))/311.89
sinT = 0.435...
Take the inverse sin.
T=25.79


295-25.79=269.21


Hence, the speed of the plane is 311.89 making the direction of 269.21 or 90.79 degrees.
Paul. 




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