Question 212940
Try this!
Let the three consecutive odd integers be:
(2x+1), (2x+3), and (2x+5).  No matter what value x is, this will guarantee that the numbers are odd.
Now you can set up the inequality as shown:
{{{135 <= (2x+1)+(2x+3)+(2x+5) <= 147}}} Simplify.
{{{135 <= 6x+9 <=147}}} Subtract 9 from all three sides(?).
{{{126 <= 6x <= 138}}} Now divide all by 6.
{{{21 <= x <= 23}}} so the three consecutive odd integers are:
{{{2x+1 = 2(21)+1}}}={{{43}}}
{{{2x+3 = 2(21)+3}}}={{{45}}}
{{{2x+5 = 2(21)+5}}}={{{47}}}