Question 212890
Well I am glad you asked this because these problems a little challenging.  The problem is I'm not sure how to explain how to do this...so i'm just going to take you step by step through the process.

{{{y = (u+1)/(u+2)}}} 
First we multiply both sides by (u+2) and get 
{{{y(u+2) = (u+1)}}}
Now we subtract u from both sides.
{{{y(u+2)-u = 1}}}
Next we distribute the y. 
{{{yu+2y-u = 1}}}
Rearrainging a little we get:
{{{yu-u+2y = 1}}}
now we factor out a u.
{{{u(y-1)+2y = 1}}}
subtract 2y from both sides.
{{{u(y-1) = 1-2y}}}
Now we divide both sides by y-1.
{{{u = (1-2y)/(y-1)}}}<br>

The next problem is somewhat similar to the problem above. First we subtract cx from both sides:
{{{ax+b-cx=d}}}
Next we rearrange a little
{{{ax-cx+b=d}}}
Subtract b from both sides
{{{ax-cx=d-b}}}
Factor out an x
{{{x(a-c)=d-b}}}
And divide by a-c
{{{x = (d-b)/(a-c)}}}