Question 212847
The cylindrical can has a length of 3*8=24 cm.
The diameter of the can is 8 cm.
The volume of the cylinder is 
V=pi*(D/2)^2*(3D)=(3/4)*pi*D^3=384*pi
The three balls have a volume of 
V=3*(4/3*pi*(D/2)^3)=(pi/2)*D^3=256*pi
Difference=(384-256)*pi=128*pi