Question 212792
{{{x^2/(x-3)}}} - {{{9/(x-3)}}}
They have the same denominators so you can write it:
{{{(x^2-9)/(x-3)}}}
(x^2-9) is the difference of squares, so we can factor it, then cancel:
{{{((x-3)(x+3))/(x-3)}}} = (x+3)