Question 212768
 the equation of of the line wich contains the point (-1,3) and has the slope negative one third
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y-y1 = m*(x-x1) m is the slope, (x1,y1) is the point
y-3 = (-1/3)*(x+1)
y = (-1/3)x + 8/3  slope-intercept form
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x + 3y = 8 standard form