Question 212745
Do you mean {{{(4/(15-3))/((5-5)/6)}}}??


If so, invert the denominator and multiply like this:
{{{(4/(15-3))*(6/(5-5))}}}
{{{(4/12)*(6/0)}}}


This is UNDEFINED, since you can NEVER divide by 0!!


R^2


Dr. Robert J. Rapalje